If x=\frac{9 t^2}{1+t^4} and y=\frac{16 t^2}{1-t^4} then \frac{d y}{d x}= [TG EAPCET 9 May 2024 Shift 1]

Correct Answer is : 169(1+t41−t4)3

\frac{16}{9} (\frac{1-t^4}{1+t^4}) ^3

\frac{16}{9} (\frac{1+t^4}{1-t^4}) ^3

TS EAMCET 9 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 65 of 160

Marks: +1, -0

If x=‌

9t2

1+t4

and y=‌

16t2

1−t4

then ‌

[TG EAPCET 9 May 2024 Shift 1]

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