© examsiri.com
Question : 6 of 160
Marks:
+1,
-0
Solution:
‌ Let ‌∆=[]On multiply
R1,R2 and
R3 by
c,a and
b, respectively
⇒∆=‌[| a2+b2 | c2 | c2 |
| a2 | b2+c2 | a2 |
| b2 | b2 | c2+a2 |
]Apply
R1⟶R1−(R2+R3)∴∆‌=‌[| 0 | −2b2 | −2a2 |
| a2 | b2+c2 | a2 |
| b2 | b2 | c2+a2 |
]‌=‌[]Apply
R2⟶R2−R1 and
R3⟶R3−R1, we get
‌=‌[]‌=‌[0−b2(a2c2−0)+a2(0−b2c2)]‌=‌(−2a2b2c2)=4abc
© examsiri.com
Go to Question: