TS EAMCET 9 May 2024 Shift 1 Solved Paper

We have, focus: (2,3) directrix : x−y+3=0 Tangent drawn at the vertex of parabola is the equation of AC.
∵AC is parallel to directrix.
∴ equation of AC is x−y+k=0...(i)
and length of BF=‌

OF

2

=‌

1

2

|‌

2−3+3

√2

|
BF=‌

1

√2

From Eq. (i), BF=|‌

2−3+k

√2

|=‌

1

√2

⇒k=2
∴ Equation of tangent is x−y+2=0