TS EAMCET 9 May 2024 Shift 1 Solved Paper

Here, coil 1 has a radius of r1 and coil 2 has a radius of r2.
Given, r1≪r2
Let current I2 flow in the coil 2 and magnetic field at its centre
B=‌

µ0I2

2r2

Since, r1≪r2
Flux through the coil, φ=‌

µ0I2

2r2

×ππ12
By definition of mutual inductance,
φ=M12I2=‌

µ0I2

2r2

πr12⇒M12=‌

µ0

2r2

πr12
Hence, mutual inductance of the arrangement is ‌

µ0

2r2

πr12.