TS EAMCET 9 May 2024 Shift 1 Solved Paper

Initial temperature of wire,
T1=303K
Final temperature of wire, T2=356K
Resistance increases \% = 10 \%
Temperature coefficient α= ?
Here, α=‌

( ∆R R0 )

∆T

‌‌... (i)
∆R= change in resistance
R= original resistance
∆T= change in temperature
∆T=T2−T1=356−303=53K
from Eq. (i),
‌α=‌

0.10

53

=1.88×10−3C−1
‌α≡2×10−3‌∘C−1
Thus, temperature coefficient of resistance of the material of the wire is approximately 2×10−3‌∘C−1.