TS EAMCET 9 May 2024 Shift 1 Solved Paper

For an equilateral prism, the angle of the prism (A) is 60∘.
If angles of incidence ( i ) and emergence
(e) are both 70% of A, then
i=e=0.7×A=0.7×60∘=42∘
The angle of minimum deviation (δm) occurs when the light path inside the prism is parallel to the base, which implies that i=e
Since, i=e, we have
δm‌=i+e−A
‌=42∘+42∘−60∘
‌=84∘−60∘
δm‌=24∘
The angle of minimum deviation is 24∘.