TS EAMCET 7 May 2018 Shift 1 Solved Paper

The equation of the circle which passes through the intersection of line and circle is given by
(x2+y2−a2)+λ(x−

a

2

)=0
Hence it passes through (2a,0). Then
(4a2−a2)+λ(2a−

a

2

)=0
λ=−2a
Hence, the equation of the circle C is
(x2+y2−a2)−2a(x−

a

2

)=0
(x−a)2+y2=a2