TS EAMCET 7 May 2018 Shift 1 Solved Paper

The position of the vectors of vertices A,B,C are a,b, and crespectively.
since, P,Q,R are mid points of AB,BC,CA .
The position vector of P,Q,R are (

a+b

2

),(

b+c

2

),(

c+a

2

)respectively.
PC−BQ=[c−(

a+b

2

)] −[(

b+c

2

)−b]
=

2c−a−b−b−c+2b

2

=

c−a

2

Now,
CP=

a+b

2

−c
=

a+b−2c

2

PQ=

c−a

2

BR=

c+a

2

−b
=

c+a−2b

2

AR=

c+a

2

−a
=

c−a

2

PC−BQ=PQ
=AR