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Question : 25 of 160
Marks:
+1,
-0
Solution:
Solving it,
sinh−12+cosh−12−tanh−1() +coth−1(−2) =ln(2+√22+1)+ln(2+√22−1) −‌ln()+‌ln() =ln[| (2+√5)(2+√3)(√3) |
| √5 |
] The formulas used here are
cosh−1x=ln(x+√x2−1) tanh−1x=‌ln() coth−1x=‌ln( )
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