TS EAMCET 7 May 2018 Shift 1 Solved Paper

First, iodine reacts with impure zirconium to form a volatile compound as shown below.
Zr( Impure )+2I2

200−500°C

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ZrI4
The volatile compound gets decomposed on heating and form pure zirconium as shown below.
ZrI4

1100°C

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Zr (Pure )+2I2