TS EAMCET 7 May 2018 Shift 1 Solved Paper

The expression for the magnetic field due to long current carrying wire at one end is,
B=

µ0i

4πd

Substitute the values in the above equation.
B=

µ0×10

4π×( 1 2 ×10−2)

B=2×10−4T
The directionof the magnetic field in both the wire is same, The total magnetic field is,
Bt=2B
Bt=2×4×10−4
Bt=8×10−4T