TS EAMCET 6-Aug-2021 Shift 2 Question Paper

Radius of the circle, r=5cm
Time period, T=5s
∴‌‌T=‌

2π

ω

(where, ω is angular velocity.) ⇒ω=‌

2π

5

rad∕s
∴ Linear speed, v=ωr=‌

2π

5

×5=2πcm∕s
As, the particle is in uniform circular motion, the centripetal force is acting on it.
∴ Centripetal acceleration is v2∕r
∴ Linear acceleration is also given as
‌‌a=‌

v2

r

=‌

4π2

5

=0.8π2cm∕s2