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Question : 32 of 160
Marks:
+1,
-0
Solution:
Let
a=P−2+3,
b=2+3−4 and
c=4+13−18 Since,
a,b,c are collinear.
⇒‌‌−2P−40+42=0 ⇒‌‌P=1 ∴‌‌AB=+5−7 and
|AB|=√75=5√3 Then, the vector on the direction of
AB=‌(+5−7‌)
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