TS EAMCET 6-Aug-2021 Shift 2 Question Paper

For a spontaneous reaction,
∆G∘= negative
Using relation, ∆G∘=∆H−T∆S
For ∆G to be negative either ∆S is + ve and ∆H is + ve at very high temperature or ∆S is + ve and ∆H is-ve at low temperature.
So, for B and C the value of ∆G∘ comes out to be negative and hence reactions are spontaneous.
So, options (c) is correct.