TS EAMCET 6-Aug-2021 Shift 2 Question Paper

The reaction is as follows

CaO

56g

+

2HNO3

126g

⟶

Ca(NO3)2

164g

+H2O
According to balanced equation, 1 mole of CaO reacts with 2 moles of HNO3 to give 1 mole of Ca(NO3)2. But the given amount of HNO3 is exactly half, i.e. 1∕2 mole. In this reaction, HNO3 act as a limiting reagent.
As 126g ( 2 moles) of HNO3⟶164g(1mol) of Ca(NO3)2
So, 56g(1mol ) of HNO3⟶‌

164

2

g of Ca(NO3)2
=82g‌ of ‌Ca(NO3)2