TS EAMCET 6-Aug-2021 Shift 2 Question Paper

Mass of helium, mHe=4g
Mass of oxygen, mO=32g
Helium is a monoatomic gas.
∴ Degrees of freedom, f1=3
Oxygen is a diatomic gas.
∴ Degrees of freedom, f2=5
4g helium contains N1=NA=6.023×1023 number of molecules
32g oxygen contains N2=NA number of molecules.
(As atomic mass of oxygen is 16g )
∴‌‌‌

Cp

CV

‌‌=γ
‌‌=‌

N1(2+f1)+N2(2+f2)

N1f1+N2f2

‌‌=‌

NA(2+3)+NA(2+5)

3NA+5NA

‌‌=‌

5+7

3+5

=‌

12

8

=‌

3

2