TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Radius of big drop =R
Number of small drops, n=64
Let radius of small drop =r In the process of breaking the drop, the volume of liquid drops remains constant.
Vi=Vf
⇒‌‌‌

4

3

πR3=n(‌

4

3

πr3)
R3=64r3⇒R=4r
⇒‌‌r=‌

R

4

Now, work done in breaking a big drop in 64 small drops.
‌‌W= final energy − initial energy
W=T(n4πr2)−T(4πR2)=4πT[64(‌

R

4

)2−R2]
=4πT[4R2−R2]=12πR2T drops.