TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Mass of boat, M=750kg
Mass of man, m=80kg
Length, L=10mLet C be the centre of mass of boat-man system when mass was at point A.
When man reaches at point B.
Let the boat displaces by x distance in opposite to displacement of man.
Then, new position of centre of mass from the reference line =x′cm
By conservation of linear momentum along the boat, distance of centre of mass from reference line remains same.
∴‌‌XCM‌‌=XCM′
‌

m×0+M L 2

m+M

‌‌=‌

m(L−x)+M( L 2 −x)

m+M

‌

ML

2

‌‌=mL−mx+‌

ML

2

−Mx
(M+m)x‌‌=mL
x‌‌=‌

mL

M+m

=‌

80×10

750+80

=0.96m
Hence, the displacement of boat is 0.96m in opposite to the displacement of man.