TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Given that,
Terminal velocity of rain, v=2m∕s
Height, h=100cm=1m
Surface area, A=1m2
Volume, V=Ah=1m3
Density of water, ρ=103kgm−3
Mass of water (rain), m=Vρ=103kg
Now, energy transferred by rain per unit area
‌‌=‌

‌ Kinetic energy ‌

‌ Area ‌

=‌

‌ 1 2 mv2

1

‌‌=‌

1

2

mv2=‌

1

2

×103×(2)2
‌‌=2×103J∕m2
Hence, energy transferred by rain to each square metre is 2×103J.