TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Given that, velocity of carA,
‌vA=30km∕h‌ (toward east) ‌
⇒‌‌vA=30

∧

i

‌ For car ‌B,vB=30km∕h‌ (toward North) ‌
⇒‌‌vB=30

∧

j

According to question,
Velocity of car B as measured in car A= relative velocity of car B w.r.t car A.
vBA=vB−vA=30

∧

j

−30

∧

i

∴ Magnitude of vBA
‌‌=√vB2+vA2=√302+302
‌‌=30√2km∕h≈42km∕h
Direction of vBA,
tan‌θ=‌

vB

vA

=‌

30

−30

=−1
⇒‌‌θ=135∘
Hence, velocity of car B as measured in car A is 42km∕h at angle of (135∘−90∘=45∘) North of West.