The general solution of \frac{dy}{dx} = {x^3(y^4+1)}/[{2y^{{-2}/3}+3(x/\sqrt^3 {y})^2}]^{3/2} is

Correct Answer is : log(y41+y4) = 49(4+3x2√2+3x2)+C

\log (\frac{y^4}{1+y^4}) = {4/9} ({4+3x^2}/\sqrt{2+3x^2})+\C

{1/4} \log (\frac{y^4}{1+y^4}) = {1/9} ({4+3x^2}/\sqrt{2+3x^2})+\C

{1/4} \log (\frac{y^4}{1+y^4}) = {4/9} ({1}/\sqrt{2+3x^2})+\C

\log (\frac{y^4}{1+y^4}) = {1/9} ({1}/\sqrt{2+3x^2})+\C

TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Section: Mathematics

Question : 80 of 160

Marks: +1, -0

The general solution of

x3(y4+1)

[2y

−2

+3(

3√y

)2]

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