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Question : 23 of 160
Marks:
+1,
-0
Solution:
√3cosec20∘−sec‌20∘=4(‌−‌) =4(‌−‌)=4(‌| ‌‌cos‌20∘−‌sin‌20∘ |
| 2‌sin‌20∘⋅cos‌20∘ |
) =4(‌| sin‌60∘⋅cos‌20∘−cos‌60∘⋅sin‌20∘ |
| sin‌40∘ |
) =4‌| sin(60∘−20∘) |
| sin‌40∘ |
=4‌=4
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