TS EAMCET 6-Aug-2021 Shift 1 Question Paper

Chlorination of propane with chlorine in presence of light gives chloropropane.
H3C−CH2−CH3+Cl2

hv

────▶

CH3CH2CH2Cl
Dehydrohalogenation in presence of alc. KOH gives propene.
CH3CH2CH2Cl

‌ Alc. ‌KOH

──────▶

CH3−CH=CH2
At high temperature terminal allylic C undergoes chlorination.
CH3−CH=CH2+Cl2

773K

──────▶

CH3−CH=CH−Cl

Allylic‌chlorination

Cl is substituted by OH
CH3−CH=CH−Cl+AgOH(aq)‌─────▶CH2‌‌=CHCH2OH