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Question : 1 of 160
Marks:
+1,
-0
Solution:
Given,
f(x)={| −2 | ‌ | −2≤x≤0 |
| x2−2 | ‌ | 0≤x≤2. |
∴‌‌|f(x)|={| 2 | ‌ | −2≤x≤0 |
| 2−x2 | ‌ | 0≤x≤√2 |
| x2−2 | ‌ | √2<x≤2. |
f(|x|)=x2−2,−2≤x≤2 ∴g(x)=|f(x)|+f(∣x)={| x2 | ‌ | −2≤x≤0 |
| 0 | ‌ | 0≤x≤√2 |
| 2(x2−2,,√2<x≤2. |
Here,
g(x) is not one-one but onto because range
=[0,4]= codomain.
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