The modulus-amplitude form of {(1-i)^{3}(2-i)}/{(2+i)(1+i)} is

Correct Answer is : 2cis(π−tan−143)

2 {\cis} (\\pi-\tan ^{-1} \frac{4}{3} )

2 {\cis} ( -\tan ^{-1} \frac{4}{3} )

2 {\cis} (-\\pi+\tan ^{-1} \frac{4}{3} )

2 {\cis} ( \tan ^{-1} \frac{4}{3} )

TS EAMCET 5 May 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 7 of 160

Marks: +1, -0

The modulus-amplitude form of

(1−i)3(2−i)

(2+i)(1+i)

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