TS EAMCET 5 May 2018 Shift 2 Solved Paper

Section: Mathematics

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Question : 63 of 160

Marks: +1, -0

If α=

Lt

x→0

x.2x−x

1−cos‌x

and β=

Lt

t→0

x.2x−x

√1+x2−√1−x2

then

α=β
α=2β
α=
β
2
α=3β

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