TS EAMCET 5 May 2018 Shift 2 Solved Paper

Consider the circle
x2+y2−4x−8y+7=0
Its centre is (2,4) and radius is r=√13
Consider the circle
x2+y2+4x+6y=0
Its centre is (-2,-3) and radius is r=√13
Consider the figure shown below.
Radius of circle C1 and C2 are equal, coordinate of B is midpoint of centre of circle C1 and C2.
Trisection of AB is,
x=

2(0)+(1)(−1)

2+1

=−

1

3

And,
y=

2( 1 2 )+(2)(1)

2+1

=

3

3

=1
Therefore, the coordinates are (−

1

3

,1).