TS EAMCET 5 May 2018 Shift 2 Solved Paper

Consider the given equations.
3x2+8xy−3y2=0
3x2+8xy−3y2 +2x−4y−1=0
Let L be the line joining the intersection point of the pairs of straight lines.
Therefore,
(3x2+8xy−3y2+2x−4y−1) −(3x2+8xy−3y2)=0
2x−4y−1=0
The line intersect the axis at (

1

2

,0) and (0,

1

4

)
Thus, the required area is,
A=

1

2

×

1

2

×

1

4

=

1

16

‌sq‌units