TS EAMCET 5 May 2018 Shift 2 Solved Paper

Section: Mathematics

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Question : 4 of 160

Marks: +1, -0

If A=[

1	2	2
2	1	2
2	2	1

] then A−1=

4I−A
A−4I
1
5
(A−4I)
1
5
(4I−A)

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