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Question : 25 of 160
Marks:
+1,
-0
Solution:
Consider the expression.
coth−13+tanh−1−cosech−1(−√3) Now,
coth−x=loge() tanh−1x=loge() And,
cosech−1x=loge() Hence,
y=coth−13+tanh−1 −cosech−1(−√3) =loge()+loge()−loge() =loge(√2.√2)+loge(√3) =loge(2√3)
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