TS EAMCET 5 May 2018 Shift 2 Solved Paper

1. The electron in orbit dx2−y2 are present in x and y axis. So, electron density is not zero.
2. Higher the value of (n+l) higher will be the energy.For 3p
n+l=3+1
=4
For‌2‌p
n+l=2+1
=3
Thus, 3p has higher energy than 2p
3. The number of angular nodes is determined by the quantum number.
4. 4f -orbital have n=4 and l=3 and the number of radial nodes‌is‌n−l−1=4−3−1
=0