TS EAMCET 5 May 2018 Shift 2 Solved Paper

The expression for the energy of a light photon is given by,
E=hf
=6.63×10−34×4×1014
=6.63×4×10−20J
=

6.63×4×10−20

1.6×10−19

eV =1.65eV
As the work function is more than the energy of incident photon, no photo emission will take place.