If f:[1, \infty) \to (5,\infty] is given by f(x)=3 x+ \frac{2}{x} then f^{-1}(x)=

Correct Answer is : 16[x+√x2−24]

\frac{1}{6} [x+\sqrt{x^{2}-24} ]

\frac{1}{6} [x-\sqrt{x^{2}-24} ]

\frac{1}{2} [1+\sqrt{x^{2}- 4} ]

TS EAMCET 5 May 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 1 of 160

Marks: +1, -0

If f:[1,∞)→(5,∞] is given by f(x)=3x+

then f−1(x)=

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