TS EAMCET 5 May 2018 Shift 1 Solved Paper

Assume A(3,2,−4) and B(9,8,−10) be two points P, divideAB in 1: 2
The coordinate of P1 is,
P1(

2×3+9

3

,

2×2+1×8

3

,

2×(−4)+1(−10)

3

)
P1(5,4,−6)
The point P2 divide AB in 2:1.
The coordinate of P2 is,
P2(

3+18

3

,

2+16

3

,

−4−20

3

)
P2(7,6,−8)
If P divides P1P2 in 1: 1 then,
The coordinate of P is,
P(

5+7

2

,

4+6

2

,

−6−8

2

)
P(6,5,−7)
since, the given coordinate of P(α,β,γ) then,
α=6
β=5
γ=−7
The given expression is calculated as,
α+2β+2γ=6+2(5)+2(−7)