TS EAMCET 5 May 2018 Shift 1 Solved Paper

The eccentricity of the ellipse is calculated as,
e=√1−(

16

25

)
=

3

5

The foci is calculated as,
Foci =(±ae,0)
=(±5(

3

5

),0)
=(±3,0)
The ends of latusrectum is,
(±ae,±

b2

a

)=(±5×

3

5

,±

16

5

)
=(±3,±

16

5

)
Consider the figure,Assume the tangents at, (3,

16

5

) is,

3x

25

+

16

5

y

16

=0

3x

25

+

y

5

=0
The area of ΔOPQ is calculated as,
area =

1

2

×

25

3

×5
=

125

6

unit ‌2
By symmetry,
The area of quadrilateral ABCD is calculated as,
Area =4×

125

6

=

250

3

unit ‌2