TS EAMCET 5 May 2018 Shift 1 Solved Paper

The equation of first circle is,
x2+y2−36=0
The equation of second circle is,
x2+y2+kx−4k−36=0
since, both the circles are intersecting orthogonally, then
−4k−36−36=0
k=−18
The equation of the required circle is expressed as,
x2+y2+(−18)x−4(−18) −36=0
x2+y2 - 18x + 36 = 0