TS EAMCET 5 May 2018 Shift 1 Solved Paper

The equation of chord passing through (0,0) and slope

3

4

is,
y=

3

4

x
3x−4y=0
Consider the figure,
The value of O1O2 is calculated as,
(O1O2)2=52−42
O1O2=3
The value of a is calculated as,
|

3(3a)−4(−4a)

√32+(−4)2

|=3
a=

3

5

The coordinate of O2 is,
O2(3(

−3

5

),−4(

−3

5

))
Thus, the coordinates of O2 are (

−9

5

,

12

5

).