TS EAMCET 5 May 2018 Shift 1 Solved Paper

Assume the slope of required line be m.
The angle between bisector x+y+1=0 and the new line is given as,
tan‌θ=|

m+1

1−m

| …… (1)
The angle between bisector x+y+1=0 and 2x+3y−4=0 is given as,
tan‌θ=|

− 2 3 + 1 3

1+ 2 3 ×1

|
=|

1

5

| …… (2)
From equations (1) and equations (2),

m+1

1−m

=(

1

5

) or

m+1

1−m

=(

−1

5

)
5m+5=1−m or 5m+5=−1+m
6m=−4 or 4m=−6
m=−

2

3

or m=−

3

2

The equation is expressed as,
x+y=−1
2x+3y=4
Solve the above equation for the value of x and y .
y=6
x=−7
The required equation is expressed as,
y−y1=m(x−x1)
(y−6)=

−3

2

(x+7)
3x+2y+9=0