TS EAMCET 5 May 2018 Shift 1 Solved Paper

Consider the equations,
√3x−y+8−4√3=0

√3x+y−12−4√3=0…… (2)
Add equation (1) and equation (2),
2√3x−4−8√3=0
x=

2(1+2√3)

√3

Subtract equation (1) and equation (2),
2y−20=0
y=10
Thus, the point of intersection of altitude is (

2(1+2√3)

√3

,10)the third altitude also passes through this point. So, the equationof third altitude is y=10.