TS EAMCET 5 May 2018 Shift 1 Solved Paper

The given expression can be expressed as,
cot

A

2

: cot

B

2

: cot

C

2

= 4 : 3 : 2 …… (1)
√

s(s−a)

(s−b)(s−c)

: √

s(s−a)

(s−b)(s−c)

: √

s(s−a)

(s−b)(s−c)

= 4 : 3 : 2

Multiply the above equation with √(s−a)(s−b)(s−c).
(s−a):(s−b):(s−c)=4:3:2

a+b+c

2

−a:

a+b+c

2

−b :

a+b+c

2

−c=4:3:2 …… (2)
From equation (1) and equation (2),
b+c−a=4k
a+c−b=3k
a+b−c=2k
Solve the above equation. Then,
a=

5k

2

b=

6k

2

c=

7k

2

The ratio of a:b:c is calculated as,
a:b:c=5:6:7