TS EAMCET 5 May 2018 Shift 1 Solved Paper

Section: Mathematics

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Question : 45 of 160

Marks: +1, -0

If Δ1 = |

1	a2	a3
1	b2	b3
1	c2	c3

| and Δ2 = |

bc	b+c	1
ca	c+a	1
ab	a+b	1

| then

Δ1

Δ2

=

ab + bc + ca
abc
2 (ab + bc + ca)
(a+b+c)2

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