TS EAMCET 5 May 2018 Shift 1 Solved Paper

Consider the figure shown below,
The expression for magnetic field at point from wire carrying current is given by
β=

µ0

4π

×

I

r

×(sin‌θ1−sin‌θ2)
The vertical distance is given as,
r=d‌sin‌α
Substitute the value in above we get,
β=

µ0

4π

×

I

r

×(sin‌90°−cos‌α)
β=

µ0I

4πd‌sin‌α

(1−cos‌α)