TS EAMCET 5 May 2018 Shift 1 Solved Paper

The reaction is as follows:
N2+3H2 → 2NH3
Let us make an I.C.E table as shown below.
The value of x can be calculated as follows:
1−x=0.7‌mol
x=0.3‌mol
The concentration of the species can be calculated as shown below.
[N2]=0.7
[H2]=1−(3×0.3)=0.1
[NH3]=1+(2×0.3)=1.6
Now the equilibrium constant can be calculated as follows.
Kc=

[NH3]2

[N2][H2]3

=

(1.6)2

(0.7)(0.1)3

=

2.56

0.0007

=3657.14