TS EAMCET 5 May 2018 Shift 1 Solved Paper

The Graham's law of diffusion states that rate (r)∝

1

√M

Where, M is the molar mass.
Also, rate (r)∝

volume(V)

time(t)

Let the given another gas be Z .

rSO2

rz

=

(V∕t)SO2

(V∕t)z

=

(1∕√M)SO2

(1∕√M)z

Rearranging the above formula we get.

VSO2×tz

Vz×tSO2

=√

Mz

MSO2

......(I)
The molar mass of SO2 is 64g∕mol.
The time can be converted to seconds as shown below.
1‌min=60‌seconds
5‌min=300 seconds
Substitute the values in equation (I).

12×300

120×60

=√

Mz

64

1

4

=

Mz

64

Mz=

64

4

Mz=16g∕mol
The molar mass of given gas is 16 g/mol.