TS EAMCET 5 May 2018 Shift 1 Solved Paper

Section: Physics

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Question : 119 of 160

Marks: +1, -0

The general solution of the differential equation x2y dx - (x3+y2) dy = 0 is

y3 = 3x2 log (cx)
c (x3−y3) = x2
log y -
x3
3y3
= c
y2−x2 = c2(y2+x2)

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