∫ 3^x/\sqrt{9^x-1} dx =

Correct Answer is : 1log3 log |3x+√9x−1| + c

1/{log3} log |3^x+\sqrt{9^x-1}| + c

1/{log3} log |3^x-\sqrt{9^x-1}| + c

1/{log9} log |3^x-\sqrt{9^x-1}| + c

1/{log9} log |9^x-\sqrt{9^x-1}| + c

TS EAMCET 5 May 2018 Shift 1 Solved Paper

Section: Physics

Question : 114 of 160

Marks: +1, -0

∫

√9x−1

dx =

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