TS EAMCET 5 May 2018 Shift 1 Solved Paper

The function f(x) is continuous on R. Then,

lim

x→1−

f(x)=

lim

x→1+

f(x)
a(−1)+b=2(−1)2+2b(−1)−

a

2

−

a

2

+3b=2 …… (1)
At x=1,

lim

x→1−

f(x)=

lim

x→1+

f(x)
−

a

2

+2b=5 …… (2)
From equation ( 1 ) and equation ( 2 ),
b=−3
Substitute the value in equation ( 1 ), then
a=−22
Thus, (a,b)=(−22,−3)