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Question : 34 of 160
Marks:
+1,
-0
Solution:
2a+3b+4c=0
|b×c|‌‌=|b||c|sin‌β=sin‌β AB‌‌=2‌ units ‌ BC‌‌=3‌ units ‌ CA‌‌=4‌ units ‌ cos‌β‌‌=‌=‌=‌ sin‌β‌‌=√1−‌=‌
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