TS EAMCET 5-Aug-2021 Shift 2 Question Paper

For 1 mole of C2H5NH2 (ethyl amine), 2 moles of CH3Cl (methyl chloride) are required to form 3∘ amine.
As given 90g of ethyl amine, hence 2 moles of C2H5NH2. Because molecular weight of C2H5NH2 is 45g.
So, for 1 mole C2H5Cl

2CH3Cl

⟶

3∘ amine
For 2 moles C2H5Cl

4CH3Cl

⟶

3∘ amine
Molecular weight of CH3Cl=50.49g∕mol
Hence, amount of methyl chloride required =4×50.49=201.96∼eq202g