TS EAMCET 5-Aug-2021 Shift 2 Question Paper

Section: Mathematics

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Question : 14 of 160

Marks: +1, -0

If x = 16C5+12C4, y =

3

∑

r=1

(20−r)C4, z =

4

∑

k=1

(16−k)C3, then x+y+z =

19×17×45
19×17×15
19×17×16
19×17×48

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